(x+2)^2-(x-1)4-5-4x=0

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Solution for (x+2)^2-(x-1)4-5-4x=0 equation: 



(x+2)^2-(x-1)4-5-4x=0

We add all the numbers together, and all the variables

-4x+(x+2)^2-(x-1)4-5=0

We multiply parentheses

-4x+(x+2)^2-4x+4-5=0

We add all the numbers together, and all the variables

-8x+(x+2)^2-1=0

We move all terms containing x to the left, all other terms to the right

-8x+(x+2)^2=1

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